2x^2+1x=210

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Solution for 2x^2+1x=210 equation:


Simplifying
2x2 + 1x = 210

Reorder the terms:
1x + 2x2 = 210

Solving
1x + 2x2 = 210

Solving for variable 'x'.

Reorder the terms:
-210 + 1x + 2x2 = 210 + -210

Combine like terms: 210 + -210 = 0
-210 + 1x + 2x2 = 0

Factor a trinomial.
(-21 + -2x)(10 + -1x) = 0

Subproblem 1

Set the factor '(-21 + -2x)' equal to zero and attempt to solve: Simplifying -21 + -2x = 0 Solving -21 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '21' to each side of the equation. -21 + 21 + -2x = 0 + 21 Combine like terms: -21 + 21 = 0 0 + -2x = 0 + 21 -2x = 0 + 21 Combine like terms: 0 + 21 = 21 -2x = 21 Divide each side by '-2'. x = -10.5 Simplifying x = -10.5

Subproblem 2

Set the factor '(10 + -1x)' equal to zero and attempt to solve: Simplifying 10 + -1x = 0 Solving 10 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1x = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1x = 0 + -10 -1x = 0 + -10 Combine like terms: 0 + -10 = -10 -1x = -10 Divide each side by '-1'. x = 10 Simplifying x = 10

Solution

x = {-10.5, 10}

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